Welcome to the personal website and blog of Adrianus Kleemans.

Check out older articles at Posts or some of my coding stuff at Projects.

Have fun, check out the most recent posts below:

Welcome to the personal website and blog of Adrianus Kleemans.

Check out older articles at Posts or some of my coding stuff at Projects.

Have fun, check out the most recent posts below:

9. January 2017

**TLDR**; Ever wondered how much a ship costs in No Man’s Sky? Here’s how much:

Inventory slots:

Average price:

Estimated gold mining time:

After playing No Man’s Sky for some time, I noticed two things about ships and slots: First, the cost of the ships available always seems to be something random around a fixed value. For a 31 slots ship, sometimes the cost is around 11.6 million, sometimes 12.3 or even 12.5.

Second, the increase per additional slot (ratio slot-price) is not linear, but instead it seems to be some kind of exponential progress.

I wondered what the real relation is between price cost and slots, so I started to take some notes. You can have a look at the 72 data points here:

(The cost is in million and rounded to a tenth of a million.)

At first, I thought the ratio from slots to price would exponential, something in the form like

(y = cost of ship, x = amount of slots) But the line is too steep for the higher slots. After playing around a bit I realized that it would be more something like the following

Here are both of the lines for comparison:

As you can see, the both rightmost points don’t really fit the first equation, whereas the second equation is a much better fit. If we look closely at the middle part between 30 and 35 slots, there the second equation also is a slightly better fit.

To fiddle out the exact parameters, I wrote a simple python script to optimize the exponent:

```
def mse(factor):
return sum([(0.000001 * entry[0]**factor - entry[1])**2 for entry in data])/len(data)
with open('data.csv', 'r') as csv_file:
content = csv_file.readlines()
data = []
for line in content:
data.append([float(line.split(',')[0]), float(line.split(',')[1].strip())])
round = 0
factor = 1.0
diff = 1.0
best_mse = 1000
best_factor = 0
while round < 100:
factor += diff
print("MSE with ", factor, ":", mse(factor))
# if new best, remember current factor
if mse(factor) < best_mse:
best_mse = mse(factor)
best_factor = factor
else:
factor = best_factor
diff = diff/2
round += 1
```

This gives the following output (to the left is the exponent, on the right the mean squared error ):

Bingo! So the formula (price in million) is:

Or in other words, for the full price, the formula is really simple:

As you can see above I also included an approximate mining time, which is based on an optimistic mining rate, for one of those planets which is full of gold piles.

For a full slot of gold, 250 units, I used 2 minutes and 30 seconds. A full slot of gold gives 55’000 units of gold, so that’s 22’000 units per minute.

Happy mining! :-)